Which is correct truth table for given circuit?

The correct truth table for the given circuit is:

Step-by-Step Analysis of the Logic Circuit:

1. Identify the Logic Gates and Connections:
- The circuit has two inputs labeled A and B on the left.
- There are two AND gates in the middle.
- There are two NOT gates (inverters) connected to the input branch lines.
- The final gate on the right is an OR (or XOR) gate producing output Z.

2. Determine the Output of the Top AND Gate:
- One input is taken directly from the input wire of A.
- The other input is taken from the input wire of B and passed through a NOT gate. Therefore, this input is $\overline{B}$ (NOT B).
- Thus, the output of the top AND gate is:
$Y_1=A·\overline{B}$

3. Determine the Output of the Bottom AND Gate:
- One input is taken from the input wire of A and passed through a NOT gate, resulting in $\overline{A}$ (NOT A).
- The other input is taken directly from the input wire of B.
- Thus, the output of the bottom AND gate is:
$Y_2=\overline{A}·B$

4. Find the Final Output Function (Z):
- The final gate combines the two outputs $Y_1$ and $Y_2$.
- Assuming an OR gate at the end, the output expression is:
$Z=Y_1+Y_2=(A·\overline{B})+(\overline{A}·B)$
- This expression represents the standard logic formula for a 2-input XOR (Exclusive OR) gate:
$Z=A\oplus B$

5. Construct the Truth Table:
- Let's evaluate the output $Z$ for all possible combinations of inputs:
- If $A=0$ and $B=0$:
$Z=(0·1)+(1·0)=0+0=0$
- If $A=0$ and $B=1$:
$Z=(0·0)+(1·1)=0+1=1$
- If $A=1$ and $B=0$:
$Z=(1·1)+(0·0)=1+0=1$
- If $A=1$ and $B=1$:
$Z=(1·0)+(0·1)=0+0=0$