What mass of silver nitrare will react with 5.85 g of sodium chloride to produce 14.35 g of silver chloride and 8.5 g of sodium nitrate, if the law of conservation of mass is true ?

The correct option is 17.0g.

To understand why this is correct, we can apply the Law of Conservation of Mass. This law states that in any chemical reaction, the total mass of the reactants must equal the total mass of the products. In other words, matter can neither be created nor destroyed.
The chemical reaction described in the problem is the reaction between silver nitrate and sodium chloride to produce silver chloride and sodium nitrate. This can be represented by the following word equation:
Silver Nitrate + Sodium Chloride → Silver Chloride + Sodium Nitrate

Let the mass of silver nitrate be represented by $x$ grams.

According to the problem, the masses of the substances involved are:
• Mass of reactants:
- Mass of Silver Nitrate = $x\text{ g}$
- Mass of Sodium Chloride = $5.85\text{ g}$
• Mass of products:
- Mass of Silver Chloride = $14.35\text{ g}$
- Mass of Sodium Nitrate = $8.5\text{ g}$

By applying the Law of Conservation of Mass, we can set up the following equation:
$$\text{Total Mass of Reactants}=\text{Total Mass of Products}$$
$$x+5.85=14.35+8.5$$

Now, simplify the right side of the equation by adding the masses of the products:
$$14.35+8.5=22.85$$
This gives us:
$$x+5.85=22.85$$

To solve for $x$ , subtract $5.85$ from both sides of the equation:
$$x=22.85-5.85$$
$$x=17.0\text{ g}$$

Therefore, the mass of silver nitrate that will react is 17.0 g.