What is the IUPAC name of the organic compound formed in the following chemical reaction ?

The correct answer is 2-methyl butan-2-ol.

Step-by-step explanation:

1. Identify the reactants from the given image:
The chemical reaction shown in the image starts with Acetone, which is reacted with:
(i) Ethylmagnesium bromide (${\text{C}}_2{\text{H}}_5\text{MgBr}$, a Grignard reagent) in the presence of dry ether.
(ii) Water in acidic medium (${\text{H}}_2\text{O},{\text{H}}^{+}$) for hydrolysis.

2. Mechanism of the Reaction:
• Step 1: Nucleophilic Addition
Acetone contains a polar carbonyl group ($\text{C}=\text{O}$):
${\text{CH}}_3-\text{CO}-{\text{CH}}_3$
The nucleophilic ethyl group ($-{\text{C}}_2{\text{H}}_5$) from the Grignard reagent attacks the electrophilic carbonyl carbon of acetone. Simultaneously, the pi-electrons of the carbonyl bond shift to the oxygen atom, forming a magnesium halide adduct:
$({\text{CH}}_3{)}_2\text{C}=\text{O}+{\text{C}}_2{\text{H}}_5\text{MgBr}\to ({\text{CH}}_3{)}_2\text{C}\left(\text{OMgBr}\right)\left({\text{C}}_2{\text{H}}_5\right)$

• Step 2: Hydrolysis
Acidic hydrolysis of the adduct protonates the oxygen atom to yield a tertiary alcohol:
$\left({\text{CH}}_3{)}_2\text{C}\right(\text{OMgBr}\left)\right({\text{C}}_2{\text{H}}_5)+{\text{H}}_2\text{O}\stackrel{{\text{H}}^{+}}{\to }({\text{CH}}_3{)}_2\text{C}\left(\text{OH}\right)\left({\text{C}}_2{\text{H}}_5\right)+\text{Mg}\left(\text{OH}\right)\text{Br}$

3. IUPAC Nomenclature of the Product:
The structure of the product is:
${\text{CH}}_3-\text{C}\left(\text{OH}\right)\left({\text{CH}}_3\right)-{\text{CH}}_2-{\text{CH}}_3$
• Find the longest continuous carbon chain containing the carbon atom bonded to the hydroxyl group ($-\text{OH}$). This chain has 4 carbon atoms, which corresponds to butane.
• Number the chain from the end closer to the hydroxyl group (from left to right):
- C-1: $-{\text{CH}}_3$ (leftmost methyl group)
- C-2: Carbon with both the $-\text{OH}$ group and a methyl ($-{\text{CH}}_3$) substituent
- C-3: $-{\text{CH}}_2-$
- C-4: $-{\text{CH}}_3$ (rightmost ethyl carbon)
• The hydroxyl group is at C-2, which gives the parent suffix butan-2-ol.
• The methyl substituent is also attached to C-2, giving the prefix 2-methyl.
• Therefore, the IUPAC name of the compound is 2-methyl butan-2-ol.