Question Details

Two gases occupy two containers A and B the gas in A, of volume 0.10m³ , exerts a pressure of 1.40 MPa and that in B of volume 0.15m³ exerts a pressure 0.7 MPa. The two containers are united by a tube of negligible volume and the gases are allowed to intermingle. Then it the temperature remains constant, the final pressure in the container will be (in MPa)

Options

A

0.70

B

0.98

C

1.40

D

2.10

Correct Answer :

0.98

Solution :

To find the final pressure of the mixture when the two containers are connected, we can apply Boyle's Law or the principle of conservation of gas molecules (or moles) at a constant temperature.

According to the Ideal Gas Law:
PV=nRT

Since the temperature (T) remains constant and the gas constant (R) is a constant, the total number of moles (n) is directly proportional to the product of pressure (P) and volume (V). That is, n=PVRT.

Let:
- For container A: volume VA=0.10 m3, pressure PA=1.40 MPa
- For container B: volume VB=0.15 m3, pressure PB=0.7 MPa

The total number of moles before mixing is the sum of the moles in both containers:
ntotal=nA+nB

Substituting n=PVRT into the equation, we get:
PfVfRT=PAVART+PBVBRT

Since temperature (T) is constant throughout, we can cancel RT from both sides, leaving:
PfVf=PAVA+PBVB

Here, the final volume Vf is the combined volume of both containers because the connecting tube has negligible volume:
Vf=VA+VB=0.10 m3+0.15 m3=0.25 m3

Now, solve for the final pressure Pf:
Pf=PAVA+PBVBVA+VB

Substitute the given values into the equation:
Pf=(1.40 MPa×0.10 m3)+(0.7 MPa×0.15 m3)0.25 m3

Calculate the products in the numerator:
- 1.40×0.10=0.14
- 0.7×0.15=0.105

Add the values in the numerator:
- 0.14+0.105=0.245

Divide by the final volume to get Pf:
Pf=0.2450.25=0.98 MPa

Thus, the final pressure in the containers is 0.98 MPa.

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