Two gases occupy two containers A and B the gas in A, of volume 0.10m³ , exerts a pressure of 1.40 MPa and that in B of volume 0.15m³ exerts a pressure 0.7 MPa. The two containers are united by a tube of negligible volume and the gases are allowed to intermingle. Then it the temperature remains constant, the final pressure in the container will be (in MPa)
Correct Answer :
0.98
Solution :
To find the final pressure of the mixture when the two containers are connected, we can apply Boyle's Law or the principle of conservation of gas molecules (or moles) at a constant temperature.
According to the Ideal Gas Law:
Since the temperature () remains constant and the gas constant () is a constant, the total number of moles () is directly proportional to the product of pressure () and volume (). That is, .
Let:
- For container A: volume , pressure
- For container B: volume , pressure
The total number of moles before mixing is the sum of the moles in both containers:
Substituting into the equation, we get:
Since temperature () is constant throughout, we can cancel from both sides, leaving:
Here, the final volume is the combined volume of both containers because the connecting tube has negligible volume:
Now, solve for the final pressure :
Substitute the given values into the equation:
Calculate the products in the numerator:
-
-
Add the values in the numerator:
-
Divide by the final volume to get :
Thus, the final pressure in the containers is 0.98 MPa.
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