The unit of absolute permittivity is

The correct option is Farad / meter.

To understand why the unit of absolute permittivity ($\epsilon$) is Farad / meter, we can start with the relation for the capacitance of a parallel plate capacitor.

The capacitance $C$ of a parallel plate capacitor is given by the formula:
$C=\frac{\epsilon ·A}{d}$
where:
• $C$ is the capacitance (measured in Farads, $F$)
• $\epsilon$ is the absolute permittivity of the medium
• $A$ is the area of the plates (measured in square meters, $m^2$)
• $d$ is the distance between the plates (measured in meters, $m$)

Rearranging the formula to solve for the absolute permittivity ($\epsilon$), we get:
$\epsilon =\frac{C·d}{A}$

Now, substituting the units of capacitance, distance, and area into this rearranged formula:
$\text{Unit of}\epsilon =\frac{\text{Farad}·\text{meter}}{{\text{meter}}^2}$

Simplifying the expression by cancelling one meter term from the numerator and denominator, we get:
$\text{Unit of}\epsilon =\frac{\text{Farad}}{\text{meter}}$

Therefore, the unit of absolute permittivity is Farad / meter (or F/m).