The total number of ions present in 111 g of CaCl2 is

The correct option is Three Mole.

To find the total number of moles of ions present in 111 g of Calcium Chloride (_CaCl2), we can break down the calculation into simple steps:

Step 1: Calculate the molar mass of _CaCl2:
The atomic mass of Calcium (Ca) is approximately 40 g/mol, and the atomic mass of Chlorine (Cl) is approximately 35.5 g/mol.
Molar mass of _CaCl2 = (Atomic mass of Ca) + 2 × (Atomic mass of Cl)
Molar mass of _CaCl2 = 40 + 2 × 35.5 = 40 + 71 = 111 g/mol.

Step 2: Determine the number of moles of _CaCl2 in 111 g:
Using the formula:
$$\text{Number of moles}=\frac{\text{Given mass}}{\text{Molar mass}}$$
Number of moles of _CaCl2 = $\frac{111\text{ g}}{111\text{ g/mol}}$ = 1 mole.

Step 3: Find the number of ions produced per formula unit of _CaCl2:
When Calcium Chloride (_CaCl2) dissociates in water, it splits completely into its constituent ions:
_CaCl2 → ^Ca2+ + 2 ^Cl-
From this balanced equation, we can see that 1 formula unit of _CaCl2 yields 1 Calcium ion (^Ca2+) and 2 Chloride ions (^Cl-), making a total of 3 ions.

Step 4: Calculate the total moles of ions:
Since 1 mole of _CaCl2 produces 3 moles of ions (1 mole of ^Ca2+ ions and 2 moles of ^Cl- ions):
Total moles of ions = 1 mole of _CaCl2 × 3 ions/formula unit = 3 moles of ions.

Therefore, the total number of ions present in 111 g of CaCl₂ is Three Mole.