The total kinetic energy of 1 mole of oxygen at 27°C is : [Take R = (25/3) J/mol-K]
Correct Answer :
6250 J
Solution :
(f = 5 for diatomic gas)
K = 5/2 μRT = 5/2 * 1 * 25/3 * 300
= 250 × 25
= 6250 J
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