The output impedance of a non-ideal operational amplifier is denoted by Zout . The variation in the magnitude of Zout with increasing frequency, f , in the circuit shown below, is best represented by
Correct Answer :
Solution :
Correct Answer: The variation of with frequency is best represented by the curve in the option containing the graph that starts flat at a lower value, increases with a constant slope at intermediate frequencies, and then flattens out again at a higher value (corresponding to the image: WhatsApp Image 2024-09-30 at 2-1727688854245.jpeg).
Explanation and Step-by-Step Derivation:
1. Understanding the Circuit Configuration
The provided circuit diagram shows a non-inverting operational amplifier with its output terminal connected directly back to its inverting input terminal (). The input voltage is applied to the non-inverting terminal (). This configuration represents a negative feedback system known as a unity-gain buffer (or voltage follower). For this configuration, the feedback factor is:
2. Formula for Closed-Loop Output Impedance
In a negative feedback amplifier, negative feedback reduces the output impedance. The closed-loop output impedance is related to the open-loop output resistance and the open-loop gain by the relation:
Since , this simplifies to:
3. Modeling the Frequency Dependence of the Open-Loop Gain
A practical, internally compensated operational amplifier has an open-loop gain that rolls off at high frequencies. This behavior is typically modeled as a single-pole low-pass transfer function:
where is the DC open-loop gain (which is very large, typically in the range of to ) and is the open-loop corner (cutoff) frequency (typically around ).
4. Deriving the Closed-Loop Output Impedance
Substitute the expression for into the output impedance formula:
5. Analysis of Frequency Regions
To determine the shape of the magnitude graph in a log-log plot (i.e., versus ), we evaluate three distinct frequency ranges:
Case I: Low Frequencies ()
Here, the frequency term is extremely small compared to , so . The output impedance becomes:
Since is a constant value, the output impedance is constant and independent of frequency in this region. This corresponds to the flat plateau at low frequencies.
Case II: Intermediate Frequencies ()
In this region, the frequency is much larger than the corner frequency , meaning , so the numerator's imaginary term dominates over 1. However, is still significantly smaller than the open-loop gain , so the denominator is dominated by :
Taking the magnitude of both sides:
Taking the logarithm:
This represents a straight line with a slope of (equivalent to ). Thus, the magnitude of output impedance increases linearly with frequency in this range.
Case III: High Frequencies ()
At very high frequencies, the term becomes much larger than both 1 and . The imaginary terms dominate in both the numerator and the denominator, leading to:
Thus, the magnitude of the output impedance levels off at a constant value equal to the open-loop output resistance , resulting in another flat horizontal region at a higher impedance value.
Conclusion
Combining the three regions, the log-log plot of vs frequency begins flat at a low impedance level (), increases linearly with a slope of at intermediate frequencies, and then flattens out at a higher value (). This is accurately depicted in the plot shown in the fourth option.
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