Question Details

The mean distance between the atoms of iron is 3 x 10⁻¹⁰ m and interatomic force constant for iron is 7 N/m. The Young’s modulus of elasticity for iron is

Options

A

2.33 x 10⁵ N / m²

B

23.3 x 10¹⁰ N / m²

C

233 x 10¹⁰ N / m²

D

2.33 x 10¹⁰ N / m²

Correct Answer :

2.33 x 10¹⁰ N / m²

Solution :

The correct option is 2.33 x 10¹⁰ N / m².

Step-by-step Explanation:

Young's modulus of elasticity (Y) of a material is related to its interatomic force constant (k) and the mean interatomic distance (r) by the formula:

Y=kr

Given data:

Interatomic force constant for iron,
k=7 N/m

Mean distance between the atoms of iron,
r=3×10-10 m

Substitute these values into the formula to find Young's modulus:

Y=73×10-10

Y=2.33×1010 N/m2

Therefore, the Young's modulus of elasticity for iron is 2.33×1010 N/m2.

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