Question
The mean and variance, respectively, of a binomial distribution for n independent trials with the probability of success as p, are
Options :
β(ππ) , ππ(1 β 2π)
β(ππ) , β(ππ(1 βp))
ππ , ππ
ππ , ππ(1 β π)
Answer :
ππ , ππ(1 β π)
Solution :
The binomial distribution of a random variable X is given by,
P(X = k) =
where n is the number of observations, p is the probability of success & q is the probability of failure.
Total probability, p + q = 1
q = 1 - p
Mean = np
Variance = npq = np(1 - p)
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