Question Details

The function f(x) = cot x is discontinuous on the set

Options

A

{x = nπ, n ∈ Z}

B

{x = 2nπ, n ∈ Z}

C

{x = (2n + 1) π/2 n ∈ Z}

D

{x – nπ/2 n ∈ Z}

Correct Answer :

{x = nπ, n ∈ Z}

Solution :

The correct option is:

{ x = n π , n Z }

To understand why this is correct, we can analyze the definition of the cotangent function. The cotangent function,

f ( x ) = cot x

is a trigonometric function defined as the ratio of the cosine function to the sine function:

cot x = cos x sin x

A function is discontinuous at any point where it is not defined. Since division by zero is undefined in mathematics, the cotangent function will be discontinuous at all values of

x

where the denominator is equal to zero. Therefore, we set the denominator to zero:

sin x = 0

The sine function is equal to zero at all integer multiples of

π

which gives the general solution:

x = n π

where

n

is any integer. Thus, the cotangent function is discontinuous on the set:

{ x = n π , n Z }

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