The following solutions were prepared by dissolving 10 g of glucose (C6H12O6) in 250 ml of water (P1), 10 g of urea (CH4N2O) in 250 ml of water (P2) and 10 g of sucrose (C12H22O11) in 250 ml of water (P3). The right option for the decreasing order of osmotic pressure of these solutions is :
Correct Answer :
P₂ > P₁ > P₃
Solution :
The correct option is P₂ > P₁ > P₃.
To find the decreasing order of osmotic pressure for the given solutions, we can use the formula for osmotic pressure (represented by the symbol ):
where:
- is the van 't Hoff factor,
- is the molar concentration (molarity) of the solute,
- is the universal gas constant, and
- is the absolute temperature.
Since glucose, urea, and sucrose are all non-electrolytes, they do not dissociate or associate in water. Therefore, their van 't Hoff factor is the same:
Additionally, the mass of each solute dissolved is the same (10 g), the volume of water is the same (250 ml), and the temperature is constant. Thus, the osmotic pressure is directly proportional to the molar concentration , which is determined by the number of moles of each solute:
Since the mass and volume are constant across all three solutions, the osmotic pressure is inversely proportional to the molar mass of the solute:
Let's calculate the molar masses of the three solutes:
1. Urea (CH₄N₂O) in solution P₂:
Molar mass = 12 (C) + 4×1 (H) + 2×14 (N) + 16 (O) = 12 + 4 + 28 + 16 = 60 g/mol.
2. Glucose (C₆H₁₂O₆) in solution P₁:
Molar mass = 6×12 (C) + 12×1 (H) + 6×16 (O) = 72 + 12 + 96 = 180 g/mol.
3. Sucrose (C₁₂H₂₂O₁₁) in solution P₃:
Molar mass = 12×12 (C) + 22×1 (H) + 11×16 (O) = 144 + 22 + 176 = 342 g/mol.
Comparing the molar masses:
Molar Mass (Urea) < Molar Mass (Glucose) < Molar Mass (Sucrose)
60 g/mol < 180 g/mol < 342 g/mol
Since osmotic pressure is inversely proportional to the molar mass of the solute for equal masses dissolved in equal volumes:
which corresponds to:
P₂ > P₁ > P₃
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