Question Details

The equation of motion for a spring-mass system excited by a harmonic force is

                                       Mẍ + Kx = F cos(ωt),

where M is the mass, K is the spring stiffness, F is the force amplitude and ω is the angular frequency of excitation. Resonance occurs when ω is equal to

Options

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D

Correct Answer :

Solution :

The correct answer is:

KM

Step-by-Step Explanation:

1. Understanding the Equation of Motion:
The equation of motion for a single-degree-of-freedom, undamped spring-mass system subjected to a harmonic excitation force is given by:

Mx··+Kx=Fcos(ωt)
where:
- M represents the mass of the system,
- K represents the spring stiffness,
- F is the amplitude of the exciting force,
- ω is the angular frequency of the exciting force, and
- x·· represents the acceleration of the mass (the second time-derivative of displacement x).

2. Finding the Natural Frequency:
The natural angular frequency of the system, denoted as ωn, is the frequency at which the system naturally vibrates when free from any external forces. We can find it by considering the homogeneous (free vibration) equation:

Mx··+Kx=0
Dividing the entire equation by mass M gives:

x··+KMx=0
Comparing this with the standard equation of simple harmonic motion, x··+ωn2x=0, we identify:

ωn2=KM
Taking the square root of both sides, the natural angular frequency is:

ωn=KM

3. Understanding Resonance:
Resonance is a physical phenomenon that occurs when the frequency of the externally applied harmonic force (ω) matches the natural frequency of vibration of the system (ωn). Under this condition, the energy transferred to the system is maximized, and for an undamped system, the amplitude of vibration theoretically increases to infinity.
Thus, resonance occurs when:

ω=ωn=KM
This corresponds to the expression shown in the correct option.

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