The electronic configuration of Neodymium (60) (Nd) is

The correct option is [Xe]4f⁴6s².

To determine the ground-state electronic configuration of Neodymium (Nd, atomic number $Z=60$), we build the electron configuration step-by-step using the Aufbau principle and the noble gas shorthand notation.

First, we identify the nearest preceding noble gas. Neodymium has an atomic number of 60. The noble gas that comes immediately before it is Xenon (Xe), which has an atomic number of 54. Using Xenon as a shortcut represents the first 54 electrons:
$\left[\text{Xe}\right]$

Next, we determine the number of remaining electrons to distribute:
Remaining electrons = $60-54=6$ electrons.

According to the Aufbau principle, after Xenon (which completes the 5th period), the next energy subshells to be filled are the 6s subshell, followed by the 4f subshell. The 6s subshell has lower energy than the 4f subshell and fills first with 2 electrons:
${\text{6s}}^2$

After placing 2 electrons in the 6s orbital, we have 4 electrons remaining ($6-2=4$). These remaining 4 electrons occupy the 4f subshell:
${\text{4f}}^4$

Combining these parts, the complete ground-state electronic configuration of Neodymium (Nd) is:
$\left[\text{Xe}\right]{\text{4f}}^4{\text{6s}}^2$