The displacement of a particle, moving in a straight line, is given by s= 2t²+2t+4 where s is in metres and t in seconds. The acceleration of the particle is

To find the acceleration of the particle, we need to analyze the relationship between displacement, velocity, and acceleration with respect to time.

First, we are given the displacement $s$ of the particle as a function of time $t$:
$s=2t^2+2t+4$

Velocity $v$ is defined as the first derivative of displacement with respect to time:
$v=\frac{ds}{dt}$

Differentiating the displacement function:
$v=\frac{d}{dt}(2t^2+2t+4)$
$v=4t+2$

Acceleration $a$ is defined as the first derivative of velocity with respect to time (or the second derivative of displacement):
$a=\frac{dv}{dt}$

Differentiating the velocity function:
$a=\frac{d}{dt}(4t+2)$
$a=4$

Since the derivative is a constant, the acceleration of the particle is constant and equal to 4 m/s².

Therefore, the correct option is 4 m/s².