The direction ratios of the normal to the plane 7x + 4y – 2z + 5 = 0 are

The correct option is 7, 4, -2.

To understand why this is the correct answer, let us look at the general equation of a plane in three-dimensional space.
The general equation of a plane is represented as:

$$ax+by+cz+d=0$$

In this general form, the coefficients $(a,b,c)$ directly represent the direction ratios of the normal vector (a vector perpendicular) to the plane.

Now, let us compare the given equation of the plane with the general equation:
Given equation:

$$7x+4y-2z+5=0$$

Therefore, the direction ratios of the normal to the plane are $(a,b,c)$, which are equal to 7, 4, -2.