The dimensions of electric potential are

The correct option is [ML²T⁻²Q⁻¹].

Step-by-step derivation:

Electric potential ($V$) is defined as the work done ($W$) per unit charge ($Q$):

$V=\frac{W}{Q}$

To find the dimensions of electric potential, we determine the dimensions of work ($W$) and charge ($Q$) first.

1. Dimensions of Work ($W$):
Work is defined as Force × Displacement. Since Force = mass × acceleration, we have:
$\left[\text{Work}\right]=\left[\text{Force}\right]\times \left[\text{Displacement}\right]$
$\left[W\right]=\left[ML{T}^{-2}\right]\times \left[L\right]=\left[M{L}^2{T}^{-2}\right]$

2. Dimensions of Charge ($Q$):
Here, the dimension of charge is represented directly by the symbol $Q$:
$\left[\text{Charge}\right]=\left[Q\right]$

3. Dimensions of Electric Potential ($V$):
Substituting the dimensional formulas of work and charge into the electric potential formula:
$\left[V\right]=\frac{\left[W\right]}{\left[Q\right]}$
$\left[V\right]=\frac{\left[M{L}^2{T}^{-2}\right]}{\left[Q\right]}$
$\left[V\right]=\left[M{L}^2{T}^{-2}{Q}^{-1}\right]$

Thus, the dimensional formula of electric potential is $\left[M{L}^2{T}^{-2}{Q}^{-1}\right]$.