Crey | The depth d at which the value of acceleration due to gravity becomes n 1/n times the value at the surface, is [R = radius of the earth] R/n, R(n-1)/n, R/n², Rn/(n+1)

Question

The depth d at which the value of acceleration due to gravity becomes n 1/n times the value at the surface, is [R = radius of the earth]

Options :

R/n
R(n-1)/n
R/n²
Rn/(n+1)

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