Question Details

The change of momentum in each ball of mass 60gm , moving in opposite directions with speeds 4m / s collide and rebound with the same speed, is

Options

A

0.98 kg-m / s

B

0.73 kg-m / s

C

0.48 kg-m / s

D

0.22kg-m / s

Correct Answer :

0.48 kg-m / s

Solution :

Correct Option: The correct answer is 0.48 kg-m / s.

To find the change in momentum of each ball, we use the definition of momentum and vector velocity.

1. Identify the Given Parameters:
Mass of each ball, m=60 gm=60×10-3 kg=0.06 kg
Initial speed of each ball, u=4 m/s

2. Define Velocity Vectors:
Let us consider the motion along a straight line (the x-axis). Since the two balls are moving in opposite directions, we can assign positive and negative directions to their velocities.
For one of the balls:
Initial velocity, vi=+4 m/s
Since the ball rebounds with the same speed in the opposite direction after the collision:
Final velocity, vf=-4 m/s

3. Calculate Initial and Final Momentum:
Initial momentum:
pi=m×vi=0.06 kg×4 m/s=0.24 kg-m/s
Final momentum:
pf=m×vf=0.06 kg×(-4 m/s)=-0.24 kg-m/s

4. Calculate the Change in Momentum:
The change in momentum (Δp) is given by the difference between the final momentum and the initial momentum:
Δp=pf-pi
Δp=-0.24 kg-m/s-0.24 kg-m/s=-0.48 kg-m/s

Taking the magnitude of this change:
|Δp|=0.48 kg-m/s

Thus, the magnitude of the change of momentum in each ball is 0.48 kg-m / s.

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