Question
Periodic time of a satellite revolving above Earth’s surface at a height equal to R, where R the radius of Earth, is [g is acceleration due to gravity at Earth’s surface]
Options :
2π √(2R/g)
4 √2 π √(R/g)
2π √(R/g)
8π √(R/g)
Answer :
4 √2 π √(R/g)
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