Question
Moment of inertia of uniform rod of mass M and length L about an axis through its centre and perpendicular to its length is given by ML²/12 . Now consider one such rod pivoted at its centre, free to rotate in a vertical plane. The rod is at rest in the vertical position. A bullet of mass M moving horizontally at a speed v strikes and embedded in one end of the rod. The angular velocity of the rod just after the collision will be
Options :
v / L
2v / L
3v / 2L
6v / L
Answer :
3v / 2L
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