[ML²T⁻²] are dimensions of

The correct option is moment of force.

To find the correct quantity, let us analyze the dimensional formulas of the options given:

1. Force:
Force is defined as mass multiplied by acceleration.
$\text{Force}=\text{mass}\times \text{acceleration}$
The dimensional formula for mass is $\left[M\right]$ and for acceleration is $\left[L{T}^{-2}\right]$.
Therefore, the dimensions of force are:
$\left[\text{Force}\right]=\left[ML{T}^{-2}\right]$

2. Moment of Force (Torque):
Moment of force is defined as the product of force and the perpendicular distance from the axis of rotation.
$\text{Moment of force}=\text{Force}\times \text{distance}$
The dimensions of distance are $\left[L\right]$.
Therefore, the dimensions of moment of force are:
$\left[\text{Moment of force}\right]=\left[ML{T}^{-2}\right]\times \left[L\right]=\left[M{L}^2{T}^{-2}\right]$

3. Momentum:
Momentum is mass multiplied by velocity.
$\text{Momentum}=\text{mass}\times \text{velocity}$
The dimensions of velocity are $\left[L{T}^{-1}\right]$.
Therefore, the dimensions of momentum are:
$\left[\text{Momentum}\right]=\left[ML{T}^{-1}\right]$

4. Power:
Power is work done per unit time.
$\text{Power}=\frac{\text{Work}}{\text{Time}}$
Work has dimensions of energy, which is $\left[M{L}^2{T}^{-2}\right]$.
Therefore, the dimensions of power are:
$\left[\text{Power}\right]=\frac{\left[M{L}^2{T}^{-2}\right]}{\left[T\right]}=\left[M{L}^2{T}^{-3}\right]$

Comparing the derived dimensions with the given dimensional formula $\left[M{L}^2{T}^{-2}\right]$, we find that it matches the dimensions of moment of force.