Measure of two quantities along with the precision of respective measuring instrument is A = 2.5 m s–1 ± 0.5 m s–1 and B = 0.10 s ± 0.01 s. The value of A B will be
Correct Answer :
(0.25 ± 0.08) m
Solution :
The correct option is (0.25 ± 0.08) m.
Let us understand how to calculate the product of two measured quantities along with its uncertainty (error limits) step-by-step.
Step 1: Identify the given values and their absolute uncertainties
The measured value of quantity A is:
A = 2.5 m s-1
The absolute uncertainty in A is:
ΔA = 0.5 m s-1
The measured value of quantity B is:
B = 0.10 s
The absolute uncertainty in B is:
ΔB = 0.01 s
Step 2: Calculate the nominal value of the product (Z = A * B)
Let Z = A * B.
Substituting the nominal values:
Z = 2.5 m s-1 * 0.10 s = 0.25 m
Step 3: Determine the relative uncertainty in the product Z
When two quantities are multiplied, their fractional or relative errors add up. The relation is given by:
Let us substitute the values into this formula:
Now, simplify the terms on the right-hand side:
First term:
0.5 / 2.5 = 1 / 5 = 0.20
Second term:
0.01 / 0.10 = 1 / 10 = 0.10
Adding them together:
0.20 + 0.10 = 0.30
Step 4: Calculate the absolute uncertainty (ΔZ)
Using the relative uncertainty:
Rounding the uncertainty to a standard format, we round 0.075 to 0.08 m (or looking at the given options, it matches 0.08 m).
Thus, expressing the value of the product A B with its uncertainty, we get:
A B = (0.25 ± 0.08) m
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