Crey | Let f : R { − 1 2 } → R and g : R − { − 5 2 } → R be defined as f ( x ) = 2 x + 3 2 x + 1 and g ( x ) = | x | + 1 2 x + 5 then the domain of the function f(g(x)) is R, R − { − 5 2 } , R − { − 1 2 , − 5 2 } , R − { − 1 2 }

Let $f : R {- \frac{1}{2}} \to R$ and $g : R - {- \frac{5}{2}} \to R$ be defined as $f (x) = \frac{2 x + 3}{2 x + 1}$ and $g (x) = \frac{| x | + 1}{2 x + 5}$ then the domain of the function f(g(x)) is

Options :

R
$R - {- \frac{5}{2}}$
$R - {- \frac{1}{2}, - \frac{5}{2}}$
$R - {- \frac{1}{2}}$

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Let $f : R {- \frac{1}{2}} \to R$ and $g : R - {- \frac{5}{2}} \to R$ be defined as $f (x) = \frac{2 x + 3}{2 x + 1}$ and $g (x) = \frac{| x | + 1}{2 x + 5}$ then the domain of the function f(g(x)) is

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