Latent heat of ice is 80 calorie/gm. A man melts 60 g of ice by chewing in 1 minute. His power is

The correct option is 336 W.

Step-by-step Explanation:

1. Identify the given values:
- Mass of the ice melted, $m=60\text{g}$
- Latent heat of fusion of ice, $L=80\text{cal/g}$
- Time taken, $t=1\text{minute}=60\text{seconds}$

2. Calculate the heat required to melt the ice:
The heat energy ($Q$) required to melt a mass ($m$) of ice is given by the formula:
$Q=m\times L$
Substituting the given values:
$Q=60\text{g}\times 80\text{cal/g}=4800\text{calories}$

3. Convert the heat energy from calories to Joules:
We know that $1\text{calorie}\approx 4.2\text{Joules}$ (using the mechanical equivalent of heat, $J=4.2\text{J/cal}$).
$Q=4800\times 4.2\text{J}=20160\text{Joules}$

4. Calculate the power developed by the man:
Power ($P$) is defined as the rate of doing work or the energy expended per unit time:
$P=\frac{Q}{t}$
Substituting the values of energy in Joules and time in seconds:
$P=\frac{20160\text{J}}{60\text{s}}=336\text{W}$

Thus, the power developed by the man is 336 W.