Question Details

In the given reaction, find value of Q value. ₆C13 → ₆C12 + ₀n1 + (Q-value) Given : mass of ₆C¹³ ⇒ x mass of ₆C¹² ⇒ y mass of ₀n¹ ⇒ z

Options

(y + x – z) C²

(y + z – x) C²

(y + z + x) C²

(z + x – y) C²

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