In four-digit integer numbers from 1001 to 9999, the digit group “37” (in the same sequence) appears ________ times.

The correct option is 280.

To find the number of times the digit group "37" appears in the four-digit numbers from 1001 to 9999, we can represent a general four-digit number as:
ABCD
where A represents the thousands digit, B represents the hundreds digit, C represents the tens digit, and D represents the units digit. Since the numbers are from 1001 to 9999, the thousands digit A must be between 1 and 9 (inclusive), while B, C, and D can be any digit from 0 to 9.

The digit group "37" can occupy three different positions in a four-digit number:

Case 1: The thousands and hundreds positions (37CD)
Here, A = 3 and B = 7.
- The tens digit C can be any of the 10 digits (0 through 9).
- The units digit D can be any of the 10 digits (0 through 9).
The number of times "37" appears in this position is:
$10\times 10=100$
times.

Case 2: The hundreds and tens positions (A37D)
Here, B = 3 and C = 7.
- The thousands digit A can be any digit from 1 to 9 (9 options, since A cannot be 0).
- The units digit D can be any of the 10 digits (0 through 9).
The number of times "37" appears in this position is:
$9\times 10=90$
times.

Case 3: The tens and units positions (AB37)
Here, C = 3 and D = 7.
- The thousands digit A can be any digit from 1 to 9 (9 options).
- The hundreds digit B can be any of the 10 digits (0 through 9).
The number of times "37" appears in this position is:
$9\times 10=90$
times.

Total Count:
By summing the occurrences from all three cases, we find the total number of times the digit group "37" appears (note that in a number like 3737, the group "37" appears twice and is correctly counted twice: once under Case 1 and once under Case 3):
$100+90+90=280$
Therefore, the digit group "37" appears 280 times.