Question Details

In Fe-Fe3C phase diagram, the eutectoid composition is 0.8 weight % of carbon at 725 °C. The maximum solubility of carbon in αferrite phase is 0.025 weight % of carbon. A steel sample, having no other alloying element except 0.5 weight % of carbon, is slowly cooled from 1000 °C to room temperature. The fraction of pro-eutectoid αferrite in the above steel sample at room temperature is

Options

A

0.387

B

0.864

C

0.475

D

0.775

Correct Answer :

0.387

Solution :

The correct option is 0.387.

To find the fraction of pro-eutectoid α-ferrite in a steel sample containing 0.5 weight % carbon when it is slowly cooled to room temperature, we apply the lever rule in the iron-carbon (Fe-Fe3C) phase diagram just above the eutectoid temperature (approx. 725 °C).

Let us identify the key compositions from the given data:
- Carbon content of the steel alloy, C0=0.5 wt% C
- Eutectoid composition (composition of austenite γ just before eutectoid reaction), Cγ=0.8 wt% C
- Maximum solubility of carbon in α-ferrite phase, Cα=0.025 wt% C

Since the overall carbon content of the steel (0.5 wt% C) is less than the eutectoid composition (0.8 wt% C), this is a hypo-eutectoid steel. Upon slow cooling from 1000 °C, the austenite phase (γ) enters the γ+α two-phase region, and pro-eutectoid ferrite (α) begins to precipitate. Just above the eutectoid temperature of 725 °C, the microstructural constituents are pro-eutectoid α-ferrite and austenite (γ).

The weight fraction of pro-eutectoid α-ferrite (Wpro-α) is calculated using the lever rule on the tie-line between Cα and Cγ:
Wpro-α = Cγ-C0 Cγ-Cα

Substituting the given values into the formula:
Wpro-α = 0.8-0.5 0.8-0.025

Let's simplify the numerator and denominator:
Wpro-α = 0.3 0.775

Performing the division yields:
Wpro-α 0.387096

Rounding to three decimal places, the fraction of pro-eutectoid α-ferrite in the steel sample is 0.387.

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