In Fe-Fe3C phase diagram, the eutectoid composition is 0.8 weight % of carbon at 725 °C. The maximum solubility of carbon in αferrite phase is 0.025 weight % of carbon. A steel sample, having no other alloying element except 0.5 weight % of carbon, is slowly cooled from 1000 °C to room temperature. The fraction of pro-eutectoid αferrite in the above steel sample at room temperature is
Correct Answer :
0.387
Solution :
The correct option is 0.387.
To find the fraction of pro-eutectoid -ferrite in a steel sample containing 0.5 weight % carbon when it is slowly cooled to room temperature, we apply the lever rule in the iron-carbon (Fe-Fe3C) phase diagram just above the eutectoid temperature (approx. 725 °C).
Let us identify the key compositions from the given data:
- Carbon content of the steel alloy,
- Eutectoid composition (composition of austenite just before eutectoid reaction),
- Maximum solubility of carbon in -ferrite phase,
Since the overall carbon content of the steel () is less than the eutectoid composition (), this is a hypo-eutectoid steel. Upon slow cooling from 1000 °C, the austenite phase () enters the two-phase region, and pro-eutectoid ferrite () begins to precipitate. Just above the eutectoid temperature of 725 °C, the microstructural constituents are pro-eutectoid -ferrite and austenite ().
The weight fraction of pro-eutectoid -ferrite () is calculated using the lever rule on the tie-line between and :
Substituting the given values into the formula:
Let's simplify the numerator and denominator:
Performing the division yields:
Rounding to three decimal places, the fraction of pro-eutectoid -ferrite in the steel sample is 0.387.
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