If the line x + y = 0 is tangent to the circle (x – λ)² + (y – β)² = 50, then (λ + β)² =

Answer :

Correct answer is : 100 $$

$\left|\frac{\mathrm{\lambda <!--\; \lambda \; -->}+\mathrm{\beta <!--\; \beta \; -->}}{\sqrt{2}}\right|=\sqrt{50}$

$|\mathrm{\lambda <!--\; \lambda \; -->}+\mathrm{\beta <!--\; \beta \; -->}|=\sqrt{100}$

$(\mathrm{\lambda <!--\; \lambda \; -->}+\mathrm{\beta <!--\; \beta \; -->}{)}^2=100$