If a body is thrown up with the velocity of 15 m/s then maximum height attained by the body is (g = 10 m/s²)

To find the maximum height attained by a body thrown vertically upwards, we can use the equations of motion under gravity.

Let's list the given parameters:
- Initial velocity, $u=15m/s$
- Acceleration due to gravity, $g=10m/s^2$
- Since the body is moving upwards, the acceleration $a$ acting on it is against the direction of motion, so $a=-g=-10m/s^2$.
- At the maximum height ($h$), the final velocity of the body becomes zero, so $v=0m/s$.

We use the third equation of motion:
$v^2=u^2+2as$
Substituting $s=h$ and $a=-g$ into the equation:
$v^2=u^2-2gh$

Now, substitute the given values into the formula:
$0^2={\left(15\right)}^2-2\times 10\times h$
$0=225-20h$
$20h=225$
$h=\frac{225}{20}$
$h=11.25m$

Therefore, the maximum height attained by the body is 11.25 m.