Question
Given that π and π are integers and π + π 2π 3 is odd, which one of the following statements is correct?
Options :
π and π are both odd
π and π are both even
π is even and π is odd
π is odd and π is even
Answer :
π is odd and π is even
Solution :
a + a2b3 is odd
Taking a common a
(1+ab3) is odd
Odd number is obtained after multiplication if both numbers multiplied are odd.
Hence, a is odd and 1+ab3 is also odd.
1+ab3 is odd, so ab3 will be even. (odd-1= even quantity)
Because a is odd so for ab3 to be even b must be even.
So, a is odd and b is even.
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