Question
Given radius of earth ‘R’ and length of a day ‘T’ the height of a geostationary satellite is [G – Gravitational constant, M – Mass of earth]
Options :
(4π²GM/T²)⁰.³³
(4πGM/R²)⁰.³³ - R
(GMT²/4π²)⁰.³³ - R
(GMT²/4π²)⁰.³³ + R
Answer :
(GMT²/4π²)⁰.³³ - R
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