Crey | Given radius of earth ‘R’ and length of a day ‘T’ the height of a geostationary satellite is [G – Gravitational constant, M – Mass of earth] (4π²GM/T²)⁰.³³, (4πGM/R²)⁰.³³ - R, (GMT²/4π²)⁰.³³ - R, (GMT²/4π²)⁰.³³ + R

Question

Given radius of earth ‘R’ and length of a day ‘T’ the height of a geostationary satellite is [G – Gravitational constant, M – Mass of earth]

Options :

(4π²GM/T²)⁰.³³
(4πGM/R²)⁰.³³ - R
(GMT²/4π²)⁰.³³ - R
(GMT²/4π²)⁰.³³ + R

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