Question
Given Knet = K1K2/K3 when Ea1 = 40 kJ/mol Ea2 = 50 kJ/mol, Ea3 = 60 kJ/mol.Calculate value of (Ea)net in kJ/mol
Answer :
Correct answer is : 30
(Ea)net = Ea1 + Ea2 - Ea3
= 40 + 50 – 60
= 90 – 60
= 30 kJ/mol
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