Question Details

For a plane electromagnetic wave propagating in x-direction, which one of the following combination gives the correct possible directions for electric field (E) and magnetic field (B) respectively ?

Options

A

B

C

D

Correct Answer :

-ĵ + k̂, -ĵ - k̂

Solution :

The correct option is:
-j^+k^,-j^-k^

Step-by-step Explanation:

1. Identify the direction of wave propagation:
The question states that the plane electromagnetic wave is propagating in the positive x-direction. Thus, the unit vector in the direction of propagation is:
s^=i^

2. Recall the properties of electromagnetic waves:
For a transverse electromagnetic wave propagating in free space:
• The electric field vector E and the magnetic field vector B are perpendicular to each other, meaning their dot product is zero:
E·B=0
• The cross product E×B points in the direction of wave propagation s^:
E×B=Ci^ (where C>0)

3. Analyze the given correct combination:
Let E=-j^+k^ and B=-j^-k^.

Check the dot product:
E·B=(-j^+k^)·(-j^-k^)
=(-1)(-1)+(1)(-1)=1-1=0
Since the dot product is 0, the electric and magnetic fields are perpendicular.

Check the direction of the cross product:
E×B=(-j^+k^)×(-j^-k^)
Using the distributive property of the cross product:
=(-j^)×(-j^)+(-j^)×(-k^)+k^×(-j^)+k^×(-k^)
Since j^×j^=0 and k^×k^=0:
=0+(j^×k^)-(k^×j^)+0
Using the cyclic cross-product relationships (j^×k^=i^ and k^×j^=-i^):
=i^-(-i^)=2i^
The resulting vector 2i^ is along the positive x-direction, which perfectly matches the wave propagation direction.

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