Dimensional formula of capacitance is

The correct option is M⁻¹L⁻²T⁴A².

To find the dimensional formula of capacitance ($C$), we can use its defining relation with charge ($Q$) and potential difference ($V$):

$C=\frac{Q}{V}$

Let's find the dimensional formulas of the individual quantities:

1. Dimensional formula of Charge ($Q$):
Electric charge is defined as the product of electric current ($I$) and time ($t$):

$Q=I\cdot t$
Using the base dimensions of current ($A$) and time ($T$):

$\left[Q\right]=\left[A^1{T}^1\right]$

2. Dimensional formula of Electric Potential ($V$):
Electric potential is work done ($W$) per unit charge ($Q$):

$V=\frac{W}{Q}$
Work done ($W$) has the same dimension as energy, which is force multiplied by distance:

$\left[W\right]=\left[M^1{L}^2{T}^{-2}\right]$
Therefore, the dimensional formula for potential difference ($V$) is:

$\left[V\right]=\frac{\left[M^1{L}^2{T}^{-2}\right]}{\left[A^1{T}^1\right]}=\left[M^1{L}^2{T}^{-3}{A}^{-1}\right]$

3. Dimensional formula of Capacitance ($C$):
Now, substitute the dimensions of $Q$ and $V$ back into the capacitance equation:

$\left[C\right]=\frac{\left[A^1{T}^1\right]}{\left[M^1{L}^2{T}^{-3}{A}^{-1}\right]}$
Simplifying the powers of base quantities:

$\left[C\right]=\left[M^{-1}{L}^{-2}{T}^4{A}^2\right]$

Thus, the dimensional formula of capacitance is M⁻¹L⁻²T⁴A².