Question
Consider adiabatic flow of air through a duct. At a given point in the duct, velocity of air is 300 m/s, temperature is 330 K and pressure is 180 kPa. Assume that the air behaves as a perfect gas with constant ๐๐ =1.005 kJ/kg.K. The stagnation temperature at this point is _________ K (round off to two decimal places).
Answer :
Correct answer is : 374.77
V = 300 m/s, T = 330 K, ฮณ = 1.4, R = 287 J/kg-K.
= 0.823
We know that,
To = 330 (1 + 0.1355) = 374.71 K
โด Stagnation temperature To = 374.71 K
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