Area bounded by the ellipse x²/4 + y²/9 = 1 is

The correct option is 6π sq. units.

To find the area bounded by the ellipse, we start with the standard equation of an ellipse:
$$\frac{x^2}{a^2}+\frac{y^2}{b^2}=1$$
where $a$ is the semi-major axis (or semi-minor axis depending on the values) and $b$ is the semi-minor axis (or semi-major axis).

The given equation of the ellipse is:
$$\frac{x^2}{4}+\frac{y^2}{9}=1$$
Comparing this with the standard equation, we get:
$a^2=4$ which gives $a=2$
and
$b^2=9$ which gives $b=3$.

The standard formula for the total area $A$ enclosed by the ellipse is:
$$A=\pi ·a·b$$

Substituting the values of $a$ and $b$ into the formula:
$$A=\pi \times 2\times 3$$
$$A=6\pi \text{ sq. units}$$

Thus, the area bounded by the given ellipse is indeed 6π sq. units.