An urn contains 6 white and 9 black balls. Two successive draws of 4 balls are made without replacement. The probability that the first draw gives all white balls and second draw gives all black balls is
Correct Answer :
3/715
Solution :
The correct option is 3/715.
Step-by-Step Explanation:
1. Understand the Initial Composition of the Urn:
The urn initially contains:
• White balls = 6
• Black balls = 9
• Total number of balls = 6 + 9 = 15
2. Probability of the First Draw (All White Balls):
We draw 4 balls from the urn. The probability that all 4 balls are white is the number of ways to choose 4 white balls out of 6 divided by the total number of ways to choose 4 balls out of 15:
3. Probability of the Second Draw (All Black Balls):
Since the draws are made without replacement, the 4 white balls drawn in the first step are not returned to the urn.
The composition of the urn before the second draw is:
• Remaining white balls = 6 − 4 = 2
• Remaining black balls = 9 (since no black balls were removed)
• Total remaining balls = 15 − 4 = 11
Now, we draw 4 balls from the remaining 11 balls. The probability that all 4 balls in this second draw are black is:
4. Calculate the Combined Probability:
The overall probability P is the product of the two probabilities:
5. Simplify the Fractions:
First, simplify the terms individually:
• For the first fraction:
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