Question Details

An urn contains 6 white and 9 black balls. Two successive draws of 4 balls are made without replacement. The probability that the first draw gives all white balls and second draw gives all black balls is

Options

A

2/335

B

1/495

C

5/812

D

3/715

Correct Answer :

3/715

Solution :

The correct option is 3/715.

Step-by-Step Explanation:

1. Understand the Initial Composition of the Urn:
The urn initially contains:
• White balls = 6
• Black balls = 9
• Total number of balls = 6 + 9 = 15

2. Probability of the First Draw (All White Balls):
We draw 4 balls from the urn. The probability that all 4 balls are white is the number of ways to choose 4 white balls out of 6 divided by the total number of ways to choose 4 balls out of 15:


P ( First draw gives all white ) = C46 C415

3. Probability of the Second Draw (All Black Balls):
Since the draws are made without replacement, the 4 white balls drawn in the first step are not returned to the urn.
The composition of the urn before the second draw is:
• Remaining white balls = 6 − 4 = 2
• Remaining black balls = 9 (since no black balls were removed)
• Total remaining balls = 15 − 4 = 11

Now, we draw 4 balls from the remaining 11 balls. The probability that all 4 balls in this second draw are black is:


P ( Second draw gives all black | First draw gives all white ) = C49 C411

4. Calculate the Combined Probability:
The overall probability P is the product of the two probabilities:


P = C46 C415 × C49 C411

As shown in the calculations from the image:


P = 15×24 15×14×13×12 × 9×8×7×6×24 24×11×10×9×8

5. Simplify the Fractions:
First, simplify the terms individually:
• For the first fraction:


15×24 15×14×13×12 = 24 14×13×12 = 2 14×13 = 1 7×13

• For the second fraction:


9×8×7×6×24 24×11×10×9×8 = 7×6 10×11

Now, multiply the two simplified fractions together:


P = 1 13×7 × 7×6 10×11

Canceling out the common factor of 7 from the numerator and denominator gives:


P = 6 13×10×11

Simplifying 610 to 35:


P = 3 13×5×11 = 3 715

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