Question
A rigid tank of volume 50 mΒ³ contains a pure substance as a saturated liquid vapour mixture at 400 kPa. Of the total mass of the mixture, 20% mass is liquid and 80% mass is vapour. Properties at 400 kPa are: π»πππ = 143.61 Β°C, ππ = 0.001084 mΒ³ /kg, ππ = 0.46242 mΒ³/kg. The total mass of liquid vapour mixture in the tank is ___________kg (round off to the nearest integer).
Answer :
Correct answer is : 135.08
mf = 0.2m, mg = 0.8m, vf = 0.001084 m3/kg, vg = 0.46242 m3/kg, V = 50 m3
V = vf Γ mf + vg Γ mg
50 = 0.001084 Γ 0.2m + 0.46242 Γ 0.8m
m = 135.08 kg
β΄ mass of liquid vapour mixture in the tank is 135.08 kg.
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