A particular station of All India Radio, New Delhi, broadcasts on a frequency of 1,368 kHz (kilohertz). The wavelength of the electromagnetic radiation emitted by the transmitter is :[speed of light, c=3.0×108 ms−1]

The correct option is 219.3 m.

The relationship between the speed of light ($c$), wavelength ($\lambda$), and frequency ($\nu$) of electromagnetic radiation is given by the formula:
$c=\lambda \times \nu$
Rearranging the formula to solve for the wavelength ($\lambda$):
$\lambda =\frac{c}{\nu }$

From the given problem, we have the following values:
Frequency, $\nu$ = 1,368 kHz = 1,368 × 10³ Hz = 1.368 × 10⁶ s^-1
Speed of light, $c$ = 3.0 × 10⁸ m s^-1

Substituting these values into the wavelength equation:
$\mathrm{��}=\frac{3.0\times {10}^8\text{m}{\text{s}}^{-1}}{1.368\times {10}^6{\text{s}}^{-1}}$
Calculating the division:
$\lambda \approx 219.298\text{m}$
Rounding to four significant figures gives:
$\lambda \approx 219.3\text{m}$

Thus, the wavelength of the electromagnetic radiation emitted by the transmitter is 219.3 m.