A particle performing simple harmonic motion in such that it’s amplitude is 4 m and speed of particle at mean position is 10 m/s. Find the distance of particle from mean position where velocity became 5 m/s.
Correct Answer :
2√ 3 m
Solution :
In 1st case : at x = 0, v = 10 m/s
then 10 =
In 2nd case :
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