Question
A particle of mass m is projected with velocity v making an angle of 45° with the horizontal. The magnitude of the angular momentum of the particle about the point of projection when the particle is at its maximum height is (where g = acceleration due to gravity)
Options :
Zero
mv³/ (4 √(2)g)
mv³/(√(2)g)
mv²/2g
Answer :
mv³/ (4 √(2)g)
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