A particle of mass ‘m’ is projected with a velocity v=kVe (k < 1) from the surface of the earth. (Ve=escape velocity) The maximum height above the surface reached by the particle is :

Options :

1. $R(\frac{k}{1-\; <!--\; -\; -->k}{)}^2$

2. R$(\frac{k}{1+k}{)}^2$

3. $\frac{R^{2}k}{1+k}$

4. $\frac{R{k}^2}{1-<!--\; -\; -->k^2}$