Question
A particle moving along the circular path with a speed v and its speed increases by ‘g’ in one second. If the radius of the circular path be r, then the net acceleration of the particle is
Options :
v²/r +g
v²/r² +g²
[v⁴/r² +g²]⁰.⁵
[v²/r +g]⁰.⁵
Answer :
[v⁴/r² +g²]⁰.⁵
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