A man walks on a straight road from his home to a market 2.5 km away with a speed of 5 km/h. Finding the market closed, he instantly turns and walks back home with a speed of 7.5 km/h. The average speed of the man over the interval of time 0 to 40 min. is equal to
Correct Answer :
45/8 km/h
Solution :
The correct answer is Option 4: 45/8 km/h.
Let's break down the motion of the man step-by-step to find his average speed over the time interval from 0 to 40 minutes.
Step 1: Analyze the journey from home to the market
The distance from home to the market is:
The speed of the man while walking to the market is:
The time taken to reach the market () is given by the formula:
Converting this time into minutes:
Step 2: Analyze the return journey from the market back towards home
The total time interval we are interested in is 40 minutes (from to ).
Since the man spent the first 30 minutes walking to the market, the remaining time for the return journey is:
Converting this remaining time into hours:
During this return journey, the man walks back with a speed of:
The distance covered by the man in these 10 minutes () is:
Step 3: Calculate the total distance covered and total time
The total distance covered by the man in the 40-minute interval is:
Expressing 3.75 as a fraction:
The total time interval is:
Step 4: Calculate the average speed
Average speed is defined as the ratio of the total distance covered to the total time taken:
Substituting the values we obtained:
Thus, the average speed of the man over the interval of 0 to 40 minutes is 45/8 km/h.
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