A horizontal force of 5 N is required to maintain a velocity of 2 m/s for a block of 10 kg mass sliding over a rough surface. The work done by this force in one minute is

The correct option is 600 J.

To find the work done by the horizontal force, we can use the fundamental definition of work done by a constant force.
The formula for work done (W) is:
$W=F·s$
where:
* $F$ is the applied force.
* $s$ is the displacement of the block in the direction of the force.

First, let's identify the given values:
* Horizontal force, $F=5\text{N}$
* Constant velocity, $v=2\text{m/s}$
* Time, $t=1\text{minute}=60\text{seconds}$

Since the block is maintaining a constant velocity, the displacement ($s$) traveled by the block in time $t$ is given by the relation:
$s=v·t$

Substituting the given values to find the displacement:
$s=2\text{m/s}·60\text{s}=120\text{m}$

Now, we calculate the work done by the horizontal force:
$W=F·s$
$W=5\text{N}·120\text{m}=600\text{J}$

Thus, the work done by the force in one minute is 600 J.