A force of 50 dynes is acted on a body of mass 5 g which is at rest for an interval of 3 seconds, then impulse is

The correct option is 1.5 x10⁻³ N - s.

Step-by-step Explanation:

Impulse is defined as the product of the average force acting on a body and the time interval for which it acts. Mathematically, it is given by the formula:
$\text{Impulse}=\mathrm{Force}\times \mathrm{Time}$
Or simply:
$J=F\times t$

From the question, we are given the following values in CGS units:
Force, $F=50\text{dynes}$
Time interval, $t=3\text{s}$
Mass, $m=5\text{g}$

First, let us compute the impulse in the CGS unit (dyne-seconds):
$J=50\text{dyne}\times 3\text{s}=150\text{dyne - s}$

Next, we need to convert the calculated impulse from CGS units (dyne-seconds) to SI units (Newton-seconds, or N - s).
We know that:
$1\text{Newton (N)}={10}^5\text{dynes}$
This gives:
$1\text{dyne}={10}^{-5}\text{N}$

Applying this conversion factor to our calculated impulse:
$J=150\times {10}^{-5}\text{N - s}$
$J=1.5\times {10}^2\times {10}^{-5}\text{N - s}$
$J=1.5\times {10}^{-3}\text{N - s}$

Thus, the impulse acted on the body is $1.5\times {10}^{-3}\text{N - s}$.