A box of mass 1 kg is pulled on a horizontal plane of length 1 m by a force of 8 N then it is raised vertically to a height of 2m, the net work done is

To find the net work done on the box, we can break the motion into two distinct parts: pulling the box horizontally and then raising it vertically. The total net work done is the sum of the work done in each phase.

Step 1: Calculate the work done during horizontal motion
The box is pulled on a horizontal plane of length $d=1\text{m}$ by a horizontal force of $F=8\text{N}$.
The formula for work done ($W_1$) during this horizontal displacement is:
$W_1=F\times d$
Substituting the given values:
$W_1=8\text{N}\times 1\text{m}=8\text{J}$

Step 2: Calculate the work done during vertical motion
The box of mass $m=1\text{kg}$ is then raised vertically to a height of $h=2\text{m}$.
The work done ($W_2$) against gravity to lift the mass is given by:
$W_2=m\times g\times h$
Taking the acceleration due to gravity $g=10{\text{m/s}}^2$:
$W_2=1\text{kg}\times 10{\text{m/s}}^2\times 2\text{m}=20\text{J}$

Step 3: Calculate the net work done
The net work done ($W_{\text{net}}$) is the sum of the horizontal and vertical work:
$W_{\text{net}}=W_1+W_2$
$W_{\text{net}}=8\text{J}+20\text{J}=28\text{J}$

Therefore, the correct option is 28 J.