A body of mass 5 kg is placed at the origin, and can move only on the x-axis. A force of 10 N is acting on it in a direction making an angle of 60° with the x-axis and displaces it along the xaxis by 4 metres. The work done by the force is

The correct option is 20 J.

Step-by-step Explanation:

To find the work done by the force, we use the standard work formula. Work done ($W$) by a constant force ($F$) when it displaces an object by a distance ($d$) at an angle ($\theta$) to the direction of displacement is given by:

$W=F·d·\cos \left(\theta \right)$

Let's identify the given values from the problem statement:
- Magnitude of the force, $F=10\text{N}$
- Displacement along the x-axis, $d=4\text{m}$
- Angle between the force and the direction of displacement (x-axis), $\theta =60°$
- Note that the mass of the body (5 kg) is given but is not needed to calculate the work done in this scenario.

Now, substitute the given values into the work formula:

$W=10·4·\cos (60°)$

Since the cosine of 60° is 0.5:

$W=10·4·0.5$

$W=40·0.5$

$W=20\text{J}$

Therefore, the work done by the force is 20 Joules (20 J).