A beaker containing a liquid is kept inside a big closed jar. If the air inside the jar is continuously pumped out, the pressure in the liquid near the bottom of the liquid will

The correct option is Decreases.

To understand why the pressure near the bottom of the liquid decreases, let us analyze the factors that determine the total pressure at a given depth in a liquid.

The total pressure $P$ at a depth $h$ below the free surface of a liquid is given by the hydrostatic pressure formula:
$P=P_0+\rho gh$
where:

• $P_0$ is the pressure of the air acting on the free surface of the liquid,
• $\rho$ is the density of the liquid,
• $g$ is the acceleration due to gravity, and
• $h$ is the depth of the liquid near the bottom.

When the air inside the closed jar is continuously pumped out, the air pressure $P_0$ above the liquid surface decreases. Because the term $\rho gh$ representing the pressure due to the liquid column remains constant, the reduction in $P_0$ directly causes the total pressure $P$ at the bottom to decrease.

Therefore, the pressure in the liquid near the bottom of the liquid will decrease.